hobot said:
Here's a great summary by Dances from the 143 mph 850 post. He agree's with my educated 4-6 hp total drag guesstimates, which is rather strange for a change. Ignore his total drive train percentage though as that has a direct relation to the power level applied, not how much hp it takes to turn a drive train to some rpm. If 5 hp lost in drive train then 50 hp crank losses 10% in path to rear patch while 100 hp would only lose 5%. BTW above don't mean 100 hp gets better gas mileage, even though its got a more efficient drive train loss compared to 50 hp with identical drive path.
This makes me laugh; consistent in missing the mark.
Your loss estimate started at 10% then 8hp
and now 4-6hp....WTF; I would not know what to agree with. :lol: I attempted to illustrate something by bounding it by the universe and you cherry pick the lowest value, the best case scenario. You grab whatever you read and run/broadcast it as your "educated...guestimate". :lol: So ok, your new guestimate is within an order of magnitude. Reminds me of the story about the chemist, engneer and statistician in a duck blind when two of them jump up and fire away at a isolated duck flying by. The chemist was 1 meter low and the engineer was 1 meter high and the statistician shouted out "you got it!"
If you agree that you are all over the road with this then yes, we do agree.
As cited in my summary elsewhere: best case of 4.8hp loss and worse case scenario is around 15hp but 10hp loss at max torque or max rpm is a reasonably good estimate between bounding conditions and is what I have presented. You cannot discount the drive train and tire loss as we are talking about RWHP (rolling road type dynos).
As an example to illustrate this point in finer detail, and if anyone is interested, there's a simple illustraton (formulas) for rolling resistance and rolling resistance HP from a tire. This is presented in the following text by John Bradley titled:
"The Racing Motorcycle - A technical guide for construction"
Using the typical laden weight of a Commando with a 200 lb rider, recommended 26 psig rear tire inflation and the factory indicated weight bias of 45.5% front and 54.5% rear (which is afwul by the way) you have the following power losses:
50 MPH 0.6HP
80 MPH 1.4HP
100 MPH 2.2HP
115 MPH 2.9HP
120 MPH 3.2HP
143 MPH 4.9HP
This is the tire rolling resistance power only and illustrates that you really need to understand numbers being reported. I wonder now if some dyno's factor this in when reporting torque, speed and power. Maybe some knowledgeable bloke who runs dynos can chime in here.
So as an example, using a primary chain efficiency of 97% and a gear box efficiency of 98% and a rear chain efficiency of 93% and a rolling road dyno pull to 115 MPH which is a reasonable speed for a well sorted stock Commando and 60 Crank shaft HP we have a mechanical loss of 7HP and from the table above a rear wheel loss of 2.9HP for a total of 9.9HP loss. Round to 10 HP since I don't know what I am doing and subtract from crankshaft horse power and I get 50 RWHP which is what I have seen on the dynos. The primary chain and gear box should be in the best of shape in terms of lubrication but the rear chain is a real crap shoot given the variety of conditions it can be in when a dyno pull is conducted.
So if you do the dyno pull in third gear you should have less tire loss (lower speed tire) but more gear box loss. What is the specific relative value of this trade off I do not know.